Subject |
Re: Drag Table to Design Form |
From |
Andy Taylor <andy.taylor@which.net> |
Date |
Mon, 21 Aug 2017 04:42:30 -0400 |
Newsgroups |
dbase.getting-started |
Norman,
Lets assume your table is called MyTable and that you have not renamed any form objects automatically created by the designer.
If you have, then you'll have to translate the names to give us the properties we need to see.
When you run the form what are the properties for:
form.MyTable1.active
form.MyTable1.requestLive
form.MyTable1.sql
form.MyTable1.rowset.autoEdit
form.MyTable1.rowset.live
The easiest way to find these is to insert the following line into the onOpen method of the form:
inspect(form.MyTable1)
If you don't yet have an onOpen method for the form put this codeblock into the onOpen method using the form designer
{;inspect(form.MyTable1)}
Andy
> I started a new form and copied an existing dbf table to Tables. I dragged the Table to the Design form and then copied existing code to the form. The sql icon appears on the design form.
>
> Using the ListBox to select a Record and running the Form produces correct results only for each of the seven original copied Records.
>
> Oddly, Entryfield values on the Form all appear the same for each of the total seven Records. I can change the Entryfields on the form and the changes are also shown in the Table. However, the changes are superficial as no new Entryfield data is processed when the Form is Run. The Form is not recognizing new input.
>
> Can someone comment on why the database table is not connecting with new Records and Entryfields on the form?
>
> Thanks, Norman Snowden
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